Question

A student was preparing to carry out an acid-base experiment and required 0.452 moles of acid. The only acid available was a bottle of hydrochloric acid labeled "40.0 % HCl by mass" and a density of 1.30 g/mL. Calculate the mass of the solution needed to supply 0.452 moles of acid.

Answer 1

We know that,

Molar mass of HCl = 36.46g/mol

Given data ,

Number of mole of HCl = 0.452mol

Step(1) Calculation for mass of HCl

We known that,

Mass = (molar mass)(Number of Mole)

Mass of HCl = (36.46g/mol)(0.452mol)

Mass of HCl = 16.48g

Step(2) Calculation mass of HCl solution.

Mass percent of HCl = 40%

We know that , mass percent will be given as follows,

Mass percent of HCl = [(mass of HCl)/(mass of solution)]×100

40 = (16.48g/mass of solution)×100

Mass of solution = (16.48g×100/40)

Mass of solution = 41.2g

Step(3) Calculation for volume of solution

Density of solution = 1.30g/mL

We know that ,

Density = mass/VOLUME

volume of solution = (mass of solution/density of solution)

Volume of solution = (41.2g)/(1.30g/mL)

VOLUME of solution = 31.69mL

Answer = 31.69mL