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A quantity of steam (150 g) at 124°C is condensed, and the resulting water is frozen...

A quantity of steam (150 g) at 124°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?

answer is in kcal

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Answer #1

The amount of heat removed

           Q = mssteam ΔT + mLv + mswΔT + mLf

              = m[ ssteam ΔT +  Lv +sw ΔT + Lf ]

               = (0.15kg) [ (0.48 kcal/kg.C) (24) + 539 kcal /kg + (1.0)(100) + 79.7 kcal/kg ]

              

              = 0.15 [ 11.52 + 539 + 100 + 79.7 ] = 109.53 kcal

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