what is the molarity of a solution prepared by dissolving 45.5 g Li2SO4 in water to 850mL total volume?
Moles of Li2SO4 = mass / molar mass
= 45.5 / 110
= 0.4136
Molarity = moles / volume ( in litre )
= 0.4136 / (850*10^-3)
= 0.4866 M
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