I highlighted the row I am having a constant syntax error issue.
import struct
record = open("block.dd")
def open(file):
try:
record = open(block.dd, "rb")
record = bytearray()
record = file.read(2048)
file.close()
finally:
return record
def search_record(x, y):
try:
search = x[y]
except(IOError):
print('Cannot search')
else:
return search
status = 0x1BE
if status == 0x80:
print("Status: Active")
else:
print("Status: Not active")
ptype = record[0x1BE+4]
print("The partition type is " + str(search_file(record, ptype))
address = struct.unpack("<i", record[0x1BE+8:0x1BE+12])
print("Address of the first sector in the partition: " + str(address[0]))1.First, you are doing something wrong in the following section
status = 0x1BE
if status == 0x80:
print("Status: Active")
else:
print("Status: Not active")
Should be like
status = record[0x1BE]
if status == 0x80:
print("Status: Active")
else:
print("Status: Not active")
2. <i means you are using little-endian integer. Make sure your format is correct.
struct.calcsize("<i") will return you 4 means it will try to read 4 bytes. Otherwise, your format of the expression is correct.
The following section works fine
>>> tup = struct.unpack('<i',
struct.pack('<i',1))
>>> print(str(tup))
(1,)
>>> print(str(tup[0]))
1
So the only problem is the packing format. Kindly check that.
I highlighted the row I am having a constant syntax error issue. import struct record =...
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