1.0256-gram sample of a compound of formula M3PO4was dissolved in water and reacted with excess calcium chloride to form 1.3736 grams of calcium phosphate via the (net ionic) reaction
3 Ca2+(aq) + 2 PO43-(aq) -------> Ca3(PO4)2(s)
Determine the identity of the metal, M
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1.0256-gram sample of a compound of formula M3PO4was dissolved in water and reacted with excess calcium...
A 5.6780 gram sample of the compound Na2XO3 was dissolved in water then reacted with excess calcium chloride: Na2XO3(aq) + CaCl2(aq) →CaXO3(s) + 2NaCl(aq) A total of 5.4842 grams of CaXO3 were collected. What is the identity of the element “X?”
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1. A 0.4187 g sample of a pure soluble chloride compound is dissolved in water, and all of the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate. The mass of the resulting AgCl is found to be 0.9536 g. What is the mass percentage of chlorine in the original compound? ________% 2. A student determines the calcium content of a solution by first precipitating it as calcium hydroxide, and then decomposing the hydroxide...
2.0 g sodium phosphate dodecahydrate (I think Na3PO4. 12H2O) and 1.0 g calcium chloride reacted. determine exact amount of reactant to eliminate a limiting reagent. I think the reaction would be: 2 Na3PO4 + 3 CaCl2 --> Ca3(PO4)2 + 6 NaCl
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A reaction is done by dissolving 5.687 g sodium phosphate and 7.533 g of calcium chloride in water. These react to form solid calcium phosphate and sodium chloride (this remains dissolved in water). a) Write a balanced equation for the reaction; don’t forget states of matter b) How many grams of calcium phosphate are expected to form if all the sodium phosphate reacts? c) How many grams of calcium phosphate are expected to form if all the calcium chloride reacts?...
A 0.5187-gram sample of calcium chloride (CaCl2;MW 110.98g/mol) was dissolved in 300. mL of water. What is the molality of the solution? (Assume the density of water is 1.00g/ml)
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A 1.42 g sample of a pure compound, with formula M_2SO_4, was dissolved in water and treated with an excess of aqueous barium chloride, resulting in the precipitation of all the sulfate ion as barium sulfate. The precipitate was collected, dried, and found to weigh 2.3.3 g. Determine the atomic mass of M, and identify M.