Question

A railroad car moves under a grain elevator at a constant speed of 3.2 m/s. 435...

A railroad car moves under a grain elevator at a constant speed of 3.2 m/s. 435 kg of grain drops into the car reducing its speed to 2.6 m/s. What is the mass of the railroad car?

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Answer #1

Solution :

Given :

Speed of car (vc) = 3.2 m/s

Mass of grain (mg) = 435 kg

Final speed of car + grains (vf) = 2.6 m/s

Let the mass of car be mc.

According to conservation of momentum :

mc vc = (mg + mc) vf

mc vc = mg vf + mc vf

mc vc - mc vf = mg vf

mc ( vc - vf )= mg vf

mc = mg vf / ( vc - vf ) = {(435 kg)(2.6 m/s)} / {(3.2 m/s) - (2.6 m/s)}

mc = 1885 kg

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