A railroad car moves under a grain elevator at a constant speed of 3.2 m/s. 435 kg of grain drops into the car reducing its speed to 2.6 m/s. What is the mass of the railroad car?
Solution :
Given :
Speed of car (vc) = 3.2 m/s
Mass of grain (mg) = 435 kg
Final speed of car + grains (vf) = 2.6 m/s
Let the mass of car be mc.
According to conservation of momentum :
mc vc = (mg + mc)
vf
mc vc = mg vf +
mc vf
mc vc - mc vf =
mg vf
mc ( vc - vf )= mg
vf
mc = mg vf / ( vc -
vf ) = {(435 kg)(2.6 m/s)} / {(3.2 m/s) - (2.6 m/s)}
mc = 1885 kg
A railroad car moves under a grain elevator at a constant speed of 3.2 m/s. 435...
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