Consider a 0.30 kg puck tied to a stake in the ice (i.e. ignore friction) with a string 0.25 m in length. The puck is moving in uniform circular motion and completes a revolution with a period of 0.23 s. What is the tension in the string in Newtons?
The tension in the string is equal to the centrifugal force
associated with the circular motion. So, if the length of the
string is L, the mass attached at the end of it is m, and the
angular frequency of the circular motion is
, then the
tension in the string is

Now re-expressing in terms of the time period T of the circular motion, we get

Where we have used

So, putting the given values,

We get the tension in the string as


Consider a 0.30 kg puck tied to a stake in the ice (i.e. ignore friction) with...
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an
ice puck of mass m revolves on an icy surface in a circle at speed
v at the end of a horizontal string of length L. the tension in the
string is T.
write the equation for centripetal force, and substitute the
values T and L appropriately. then with a bit of elementary
algebra, rearrange the equation so that it solves for mass.
find the mass of the puck when the length of the string is 2.0
m, string...
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