Question

Write a simple pseudocode for this program:

Prompt the user for their birthday and then determine the number of days between today and the users birthday and calculate their age

Answer 1

Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries.

#include <stdio.h>
#include <stdlib.h>
void findAge(int current_date, int current_month,
int current_year, int birth_date,
int birth_month, int birth_year)
{
int month[] = { 31, 28, 31, 30, 31, 30, 31,
31, 30, 31, 30, 31 };

if (birth_date > current_date) {
current_date = current_date + month[birth_month - 1];
current_month = current_month - 1;
}

if (birth_month > current_month) {
current_year = current_year - 1;
current_month = current_month + 12;
}

int calculated_date = current_date - birth_date;
int calculated_month = current_month - birth_month;
int calculated_year = current_year - birth_year;
int i,daym=0;
for(i=0;i<calculated_month;i++)
{
daym=daym+month[i];
}
printf("Total days are %d ",calculated_year*365+calculated_date+daym);
printf("Present Age Years: %d Months: %d Days:"
" %d ", calculated_year, calculated_month,
calculated_date);
}

int main()
{
int current_date = 12;
int current_month = 1;
int current_year = 2019;

int birth_date = 16;
int birth_month = 12;
int birth_year = 2009;

findAge(current_date, current_month, current_year,
birth_date, birth_month, birth_year);
return 0;
}

Kindly revert for any queries

Thanks.