Question

Complete each equation by wriing the formulas of the products. For each reaction, identify the acid...

Complete each equation by wriing the formulas of the products. For each reaction, identify the acid and base as strong or weak by writing SA, SB, WA, WB on the line under the reactant. Then predict whether the salt formed will be neutral, acidic, or basic in solution. Explain your reasoning.

a. HCl(aq) + NaOH(aq) ---->

________ ________

b. HC2H3O2(aq) + NaOH(aq) ---->

------------ ------------

C. HCl(aq) + NH3(aq) ---->

________ ________

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Answer #1

Question)

(A.)

HCl - Strong acid

NaOH - Strong base

~ Salt formed will be neutral.

Reaction :

NaCl undergoes dissociation into respective ions when dissolved in water :

(B.)

CH3COOH or HC2H3O2 - Weak acid

NaOH - Strong base

~ Salt formed will be basic.

Reaction :

CH3COONa undergoes dissociation into respective ions when dissolved in water as follows :

Acetate ions produced due to dissociation of sodium acetate undergoes reaction with water as follows :

Acetic acid produced remains unionised as it is a weak acid. Solution becomes alkaline due to extra hydroxyl ions liberated.

(C.)

HCl - Strong acid

NH​​​​​3 - Weak base

~ Salt formed will be acidic.

Reaction :

Ammonium chloride when dissolved in water undergoes dissociation into respective ions as follows:

Ammonium ions produced react with water as follows:

Ammonia since is weak base do not undergo dissociation or we can say, remains unionised. Thus, hydronium ions produced impact extra acidity to solution. Therefore, solution becomes acidic.

​​​​​​

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