Question

Objected Oriented Programming

Exception Handling

Create an EmployeeException class whose constructor receives a String that consists of an Employee’s ID and pay rate. Create an Employee class with two fields, IDNum and hourlyWage. The Employee constructor requires values for both fields. Upon construction, throw an EmployeeEception if the hourlyWage is less than 6.00 or over 50.00. Write a test program (containing main method) that establishes at least three employees with hourlyWages that are above, below, and within the allowed range.

Answer 1

class EmployeeException extends Exception
{
EmployeeException(String IDPayRate)
{
super(IDPayRate);
}
}
class Employee
{
int IDNum;
double hourlyWage;

Employee(int IDNum,double hourlyWage)
{
this.IDNum=IDNum;
if(hourlyWage>50.00 || hourlyWage<6.00)
{
try
{
throw new EmployeeException(IDNum+" "+hourlyWage+"\n");
}
catch(EmployeeException e1)
{
System.out.println(e1);
}
}
else
{
this.hourlyWage=hourlyWage;
}
}
void employeeInfo()
{
System.out.println("Employee's ID : "+IDNum);
System.out.println("Employee's Hourly wages : "+hourlyWage);
}
}

class Test
{
public static void main(String args[])
{
System.out.println("HourlyWages that are above : ");
Employee e1=new Employee(1,60.00);
System.out.println("HourlyWages that are below : ");
Employee e2=new Employee(2,5.00);
System.out.println("HourlyWages that are within the allowed range : \n");
Employee e3=new Employee(3,25.00);
e3.employeeInfo();
}
}

Note :Taken employeeInfo() method for more understanding