3.1. Convert the contingency table to show the conditional distribution of cigarette use. Show your work....
3.1. Convert the contingency table to show the conditional distribution of cigarette use. Show your work. Hint: Find P(cigarette=yes|alcohol=yes) etc.
| Alcohol Use | Cigarette Use | ||
| Yes | No | ||
| Yes | 1200 | 400 | |
| No | 300 | 200 | |
Homework Answers
joint distribution is :
| Yes | No | total | |
| yes | 1200 | 400 | 1600 |
| No | 300 | 200 | 500 |
dividing each value in joint distribution with row total, below is conditon distribution of cigrette use:
| Yes | No | |
| yes | 1200/1600=0.75 | 400/1600=0.25 |
| No | 300/500=0.6 | 200/500=0.4 |
from above: P(cigarette=yes|alcohol=yes) =0.75
P(cigarette=no|alcohol=yes) =0.25
P(cigarette=yes|alcohol=no) =0.60
P(cigarette=no|alcohol=no) =0.4
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3.1. Convert the contingency table to show the
conditional distribution of cigarette use. Show your work....
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