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1. The determined Wile E. Coyote is still chasing the Road Runner since last week's homework....

1. The determined Wile E. Coyote is still chasing the Road Runner since last week's homework. He is still strapped to the same rocket, giving him an acceleration in the x-direction of 15 m/s2. The coyote chases the Road Runner to the edge of a cliff, where the Road Runner magically continues, and the coyote goes off the cliff. The coyote velocity is completely horizontal and has a magnitude of 47.7 m/s as he goes over the edge. If the cliff is 100 m above the base of a canyon, find where the coyote lands in the canyon. (Assume that his rocket is still in operation when he is in "flight" and that his horizontal component of acceleration remains constant at 15 m/s2.

2. In the movie Furious 7, the heroes Dom and Brian jump a car out of one of the Etihad Towers in Abu Dhabi and land inside another of the towers a few floors lower. The buildings are 45.7m away from each other. Let's say they start about 50 stories high, which is 200.m off the ground. If the car leaves the building traveling at 27.5 m/s at an angle of 12.0˚, how high off the ground does the car hit the 2nd building?

3. Jessica Jones, in an effort to defend her fellow Defenders, throws a car through a plate glass window of a restaurant. She launches the car with an initial velocity of 11.0 m/s at an angle of 15.0˚. The car hits the window at the same height she threw it from (as in y=y0). How far away was she from the window before throwing the car?

4. In the Donkey Kong Country video games, you often get around by shooting yourself out of barrel cannons. Donkey Kong wants to launch out of one barrel and land in a different one that is a distance in x of 9.28 m away. To do so he launches himself at a velocity of 19.5 m/s at an angle of 30.0˚. At what height does the 2nd barrel need to be for Donkey Kong to land in it? (measure from the height of barrel 1, aka y0=0)

5. The Incredible Hulk travels from place to place by taking huge leaps according to the comic books. Also according to the comic books, the Hulk can leave the ground with an initial velocity of 210. m/s. If the Hulk leaves the ground at an angle of 30˚, how far can he travel in x? Assume he lands at the same height he left the ground at (y=y0)

6. Hawkeye (from The Avengers) wants to shoot a distant criminal. To do this, he fires an arrow horizontally to try to hit the criminal who is 50.0 m away from him. If he shoots the arrow from 1.30 m above the ground (approximately chest high) at an initial velocity of the magnitude of 264.9. miles per hour at what height is the arrow when it travels the 50.0 m? (1 mile = 1609 meters)

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Answer #1

(1)
Initial velocity in the horizontal direction (u) = 47.7 m/s
Acceleration in the horizontal direction (ax) = 15 m/s2
Initial velocity in the vertical direction (uy) = 0 m/s
Height of the cliff (H) = 100 m
Considering the vertical motion

Now, considering the horizontal motion

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