Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads and the total cost to reduce N loads to a particular waterbody (assume an improved fishery is the only benefit of N reduction). What total N load reduction would maximize total fishery benefits (the level associated with highest overall "environmental quality")?
| Total Q of N reduction | Total Fishery Benefits | Total N Abatement Cost |
| 0 | 0 | 0 |
| 100,000 | $1,000,000 | $300,000 |
| 200,000 | $1,800,000 | $700,000 |
| 300,000 | $2,400,000 | $1,250,00 |
| 400,000 | $2,700,000 | $2,300,000 |
| 500,000 | $2,900,000 | $4,300,000 |
| 600,000 | $3,000,000 | $8,300,000 |
| 700,000 | $3,050,000 | $18,300,000 |
100,000
200,000
300,000
400,000
500,000
600,000
700,000
Question 12
Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads and the total cost to reduce N loads to a particular waterbody (assume an improved fishery is the only benefit of N reduction). What is the marginal abatement cost of reducing N loads from 400,000 to 500,00 lbs?
| Total Q of N reduction | Total Fishery Benefits | Total N Abatement Cost |
| 0 | 0 | 0 |
| 100,000 | $1,000,000 | $300,000 |
| 200,000 | $1,800,000 | $700,000 |
| 300,000 | $2,400,000 | $1,250,00 |
| 400,000 | $2,700,000 | $2,300,000 |
| 500,000 | $2,900,000 | $4,300,000 |
| 600,000 | $3,000,000 | $8,300,000 |
| 700,000 | $3,050,000 | $18,300,000 |
$3
$9
$10
$20
11. 700,000
(We can see that the maximum value of total fishery benefits is
$3,050,000 at total N load reduction = 700,000)
12. $20
(Marginal abatement cost = Change in total abatement cost/Reduction
in N loads
= (4,300,000-2,300,000)/(500,000-400,000) = 2,000,000/100,000 =
20)
Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads...