Question

Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads...

Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads and the total cost to reduce N loads to a particular waterbody (assume an improved fishery is the only benefit of N reduction). What total N load reduction would maximize total fishery benefits (the level associated with highest overall "environmental quality")?

Total Q of N reduction Total Fishery Benefits Total N Abatement Cost
0 0 0
100,000 $1,000,000 $300,000
200,000 $1,800,000 $700,000
300,000 $2,400,000 $1,250,00
400,000 $2,700,000 $2,300,000
500,000 $2,900,000 $4,300,000
600,000 $3,000,000 $8,300,000
700,000 $3,050,000 $18,300,000

100,000

200,000

300,000

400,000

500,000

600,000

700,000

Question 12

Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads and the total cost to reduce N loads to a particular waterbody (assume an improved fishery is the only benefit of N reduction). What is the marginal abatement cost of reducing N loads from 400,000 to 500,00 lbs?

Total Q of N reduction Total Fishery Benefits Total N Abatement Cost
0 0 0
100,000 $1,000,000 $300,000
200,000 $1,800,000 $700,000
300,000 $2,400,000 $1,250,00
400,000 $2,700,000 $2,300,000
500,000 $2,900,000 $4,300,000
600,000 $3,000,000 $8,300,000
700,000 $3,050,000 $18,300,000

$3

$9

$10

$20

0 0
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Answer #1

11. 700,000
(We can see that the maximum value of total fishery benefits is $3,050,000 at total N load reduction = 700,000)

12. $20
(Marginal abatement cost = Change in total abatement cost/Reduction in N loads
= (4,300,000-2,300,000)/(500,000-400,000) = 2,000,000/100,000 = 20)

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