Ch.22 #11
A 1.62-m-long FM antenna is oriented parallel to the electric field of an EM wave.
Part A
How large must the electric field be to produce a 1.05-mV (rms) voltage between the ends of the antenna?
Part B
What is the rate of energy transport per square meter?
Solution)
Part a)
We know,
Electric Field, E=V(rms)/d
= 1.05*10^-3/1.62 m
=0.000648 V/m
========
Part b)
Now,
Rate of Energy=?
We know, Electruc Field, E =c*εo*E^2
Here,
E = 0.000648 V/m
So,
Rate of energy= 3*10^8*8.854*10^-12*(0.000648)^2
= 1.15*10^-9 W/m^2
===============
Ch.22 #11 A 1.62-m-long FM antenna is oriented parallel to the electric field of an EM...
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