The resistance of a metal wire 1m long is measured and is found to be 0.1Ω....
The resistance of a metal wire 1m long is measured and is found to be 0.1Ω. The wire is then formed into a circular ring, with the two ends of the wire welded together so that the joint has negligible resistance. A uniform magnetic field perpendicular to the plane of the ring increases at a constant rate from 0 Tesla to 2 Tesla. How much charge moves through the joint in the metal ring during this process?
Homework Answers
Let time taken be t,
induced voltage = Area*dB/dt
V = pi*r^2*B/t
= pi*(1/(2pi))^2*2/t
current i = V/R
charge q = i*t = pi*(1/(2pi))^2*2/t*t/R
= pi*(1/(2pi))^2*2/0.1
= 1.59 C answer
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The resistance of a metal wire 1m long is measured and is found
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Two parallel rails with negligible resistance are 1.00E-1m apart
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the resistor at constant speeds v1=4.00m/s and v2=2.00m/s,
respectively. A uniform magnetic field of magnitude 0.0100T is
applied perpendicular to the plane of the rails. Determine the
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