. A 3.4 kg block is initially at rest. This block is pushed in the +x...
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A 3.4 kg block is initially at rest. This block is pushed in the +x direction by a constant, horizontal force = 54.8 N over a level surface that is of varying materials, and so its effective coefficient of friction is dependent upon the position, x. This coefficient of friction can be calculated as a function x: 0.5(1-x/4), so it decreases as the block moves from its initial position to its final position, 4 meters further in the +x direction, ending at 0 when x = 4 m. Find the block's speed when it has moved the 4 meters. Enter your answer to the tenth's place.
HINT: Notice that the equation for the coefficient of friction is based on postiion, x, and not time, t. And so, you should look to set-up the equations in terms of dx instead of dt. Remember that the chain rule shows: ax =dvx/dt = vx dvx/dx. You can use this to rewrite the differential equation from a derivative with respect to time into a derivative with respect to position. See the top of p. 280 for this result.
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A 3.4 kg block is initially at rest. This block is pushed in the
+x...
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