HomeworkLib
Question

Determine the inductance of a coil 14.9 mm in diameter, 30.5 mm in length, and carrying...

Determine the inductance of a coil 14.9 mm in diameter, 30.5 mm in length, and carrying 679 wraps of fine wire. Express in milli-Henry.

science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

In milli henry inductance = 4.88 x 10-3 mH

Please rate it up thanks :)

0 0
Add a comment
Know the answer?
Add Answer to:
Determine the inductance of a coil 14.9 mm in diameter, 30.5 mm in length, and carrying...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • A 30.0 cm diameter coil consists of 37 turns of cylindrical copper wire 2.40 mm in...

    A 30.0 cm diameter coil consists of 37 turns of cylindrical copper wire 2.40 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.50 x 10-3 T/s. Determine the current in the loop in milli-amps (the resistivity for copper is 1.72 x 10-8 Ω.m).

  • A 29.0 cm diameter coil consists of 23 turns of cylindrical copper wire 2.00 mm in...

    A 29.0 cm diameter coil consists of 23 turns of cylindrical copper wire 2.00 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7 x 10^-3 T/s. Determine the current in the loop in milli-amps (the resistivity for copper is 1.72 x 10^-8 Ω.m).

  • #16 A 22.0-cm-diameter coil consists of 28 turns of circular copper wire 2.6 mm in diameter....

    #16 A 22.0-cm-diameter coil consists of 28 turns of circular copper wire 2.6 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.65 Times 10^-3 T/s. Determine the current in the loop, and the rate at which thermal energy is produced. A power line carrying a sinusoidally varying current with frequency f = 60 Hz and peak value I_0 = 55 kA runs at a height of 7.0 m across...

  • A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter....

    A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) Determine the rate at which thermal energy is produced. (Express your answer to two significant figures and include the appropriate units.)

  • A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter....

    A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s .The resistivity of copper is 1.68×10−8Ω⋅m. a) Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) b) Determine the rate at which thermal energy is produced.(Express your answer to two significant figures and include the appropriate units)

  • A current-carrying gold wire has a diameter of 0.90 mm. The electric field in the wire...

    A current-carrying gold wire has a diameter of 0.90 mm. The electric field in the wire is 0.51 V/m. Submit Request Answer Part C What is the resistance of a 6.7-m length of this wire? Express your answer using two significant figures. o ACP O O ? R= Submit Request Answer

  • After you measure the self-inductance of a coil, you unwind it and then rewind one third...

    After you measure the self-inductance of a coil, you unwind it and then rewind one third the length of the wire into a coil with the same diameter and third length and with half the number of turns. How does this change the self-inductance? L = μ₀n^(2)AI Please show me how the final equation comes about.

  • A solenoid consists of a coil with length 68 mm, a radius of 23 mm, and...

    A solenoid consists of a coil with length 68 mm, a radius of 23 mm, and 278 turns. What is the inductance of the coil? Remember to calculate the cross sectional area.

  • A technician wraps wire around a tube of length 40 cm that has a diameter of...

    A technician wraps wire around a tube of length 40 cm that has a diameter of 6 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 600 turns of wire. A) determine the self inductance of this solenoid B) if the current in this solenoid were to increase at a rate of 5A/s, what would be the induced potential in the solenoid?

  • The standard equation used by Hams and engineers to calculate the inductance of a solenoid coil...

    The standard equation used by Hams and engineers to calculate the inductance of a solenoid coil is Wheeler’s formula (1928). It is L=(a^2 n^2)/(2.54×(9a+10b)) , where L is the inductance in microhenry, a is the coil radius in cm, and b is the coil length in cm and n is the total number of turns. We are now designing a solenoid coil for a solid-state NMR probe, aiming at a coil of 0.05 microhenry as the inductance. Please notice that...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT