Question

Write a C++ program using function that takes a Two Dimensional array, number of rows and number of columns in
that array as argument, and returns another 2D-array containing binary representation of those
numbers.

Answer 1

Refer to screenshots for Indentation and Comments

CODE :

#include <iostream>
#include <math.h>
using namespace std;    
long long** binary_array(int** int_array,int n, int m);          // Declaration of function
int main () {
    int n,m;
    cout<<"Enter number of rows : ";                      
    cin>>n;                                                      // Number of rows
    cout<<"Enter number of columns : ";
    cin>>m;                                                      // Number of columns
    int** int_array=new int*[n];                                 // Dynamic 2-D array with memory allocation using new
    cout<<"Enter the respective values of 2-D array : "<<endl;
    for(int i=0;i<n;i++)
    {
        int_array[i]=new int[m];                                    // Allocating memory for i'th row
        for(int j=0;j<m;j++)
            {
                int t;
                cin>>t;
                int_array[i][j]=t;                                  // input value of ith row and jth columns
            }  
    }
    long long** bin_array = binary_array(int_array,n,m);            // function call
    cout<<"Binary representation of each number is : "<<endl;
    for (int i = 0; i < n; i++)
    {
        for(int j=0;j<m;j++)
            cout<<bin_array[i][j]<<"\t";                            // printing the result
        cout<<endl;
    }
    return 0;
}

long long** binary_array(int** int_array,int n, int m)              // function definition
{
    long long** bin;
    bin = new long long*[n];                                        // 2-D dynamic array
    for(int i=0;i<n;i++)
    {
        bin[i] = new long long[m];                                  // Allocating memory for i'th row
        for(int j=0;j<m;j++)
        {
            int repres[20];
            int k=0;
            long long temp = 0;
            int val = int_array[i][j];
            while(val)
            {
                repres[k]=val%2;                                     //Calculating and storing the binary representation
                val=val/2;
                k++;
            }
            while(k--)
            {
                if(repres[k]==1)
                temp+=pow((long long)10,(long long)k);                  // Loop to store binary value of each value in our integer array
            }
            bin[i][j]=temp;
        }
    }
    return bin;                                                         // return the binary array
}

Snapshots of CODE

SAMPLE OUTPUT :