The catalytic converter in an automobile has to be able to convert NO2(g) produced in an engine into N2(g) and O2(g), according to the reaction:
NO2(g) ⇌ 1⁄2 N2(g) + O2(g)
The equilibrium constants (at 298 K) for the following reactions are known:
1⁄2 N2(g)+ 1⁄2 O2(g)⇌NO(g) Kc1 =6.6×10^-16
2 NO2(g) ⇌ 2 NO(g) + O2(g) Kc2 = 3.3 × 10^-13
a. What is value of Kc for the decomposition of NO2 at 298K?
b. Are the products favored at equilibrium?
The catalytic converter in an automobile has to be able to convert NO2(g) produced in an...
1. As an EPA scientist studying catalytic converters and urban smog, you want to find Kc for the following reaction: 2 NO2 (g) ⇋ N2(g) + 2 O2(g) Kc = ?? Use the following data to find the unknown Kc: 1/2 N2 (g) + 1/2 O2 (g) ⇋ NO (g) Kc = 0.004 2NO2 (g) ⇋ 2NO (g) + O2 (g) Kc = 0.069 2. A chemical reaction between X2 and Y2 produces XY. All compounds are in a gaseous...
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The air pollutant NO is produced in automobile engines from the high-temperature reaction N2(g)+O2(g)⇌2NO(g);Kc=1.7×10−3 at 2300 K. If the initial concentrations of N2 and O2 at 2300 K are both 1.58 M, what are the concentrations of NO when the reaction mixture reaches equilibrium? Concentrations of NO= UNITS If the initial concentrations of N2 and O2 at 2300 K are both 1.58 M, what are the concentrations of N2 when the reaction mixture reaches equilibrium? Concentrations of O2= If the...
The air pollutant NO is produced in automobile engines from the high-temperature reaction: N2(g)+O2(g)⇌2NO(g)Kc=1.7×10−3. Calculate the equilibrium concentrations if the initial concentrations are 2.28 M N2 and 0.56 M O2. (This N2/O2concentration ratio is the ratio found in air.) Express your answer using two significant figures. Enter your answers numerically separated by commas.