1-
A Styrofoam cup holds 0.282 kg of water at 25.5°C. Find the final equilibrium temperature (in degrees Celsius) after a 0.123 kg block of iron at 85.1°C is placed in the water. Neglect any thermal energy transfer with the Styrofoam cup. The specific heats of water and iron are cwater = 4186
| J |
| (kg · °C) |
and cFe = 448
| J |
| (kg · °C) |
.
2- A(n) 70-g ice cube at 0°C is placed in 710 g of water at 22°C. What is the final temperature of the mixture?
3- A 53-g ice cube at 0°C is heated until 45.8 g has become water at 100°C and 7.2 g has become steam at 100°C. How much energy was added to accomplish the transformation?
4- How much energy is required to change a 30-g ice cube from ice at −20°C to steam at 115°C?
1- A Styrofoam cup holds 0.282 kg of water at 25.5°C. Find the final equilibrium temperature...
A 9.0x10-2-kg ice cube at 0.0 ° C is dropped into a Styrofoam cup holding 0.35 kg of water at 10 °C. You may want to review (Pages 607-608) Find the initial temperature of the water that would be enough to just barely melt all of the ice. Find the final temperature of the system. Assume the cup and the surroundings can be ignored.Find the amount of ice (if any) remaining.
A piece of metal with a mass of 25.5 at 169.9oC is placed in a styrofoam cup containing 35.0 g of water at 24.3oC. Once the system has reached equilibrium, the final temperature of the water is 34.0oC. What is the specific heat of the metal to four significant digits? The specific heat of water is 4.18 J/g-oC.
A 46.5 g ice cube, initially at 0°C, is dropped into a Styrofoam cup containing 384 g of water, initially at 21.6°C. What is the final temperature of the water, if no heat is transferred to the Styrofoam or the surroundings?
A 0.15 kg ice is placed into an aluminum cup with 0.3 kg water in it. The initial temperature of cup is 60°C and the mass of the aluminum cup is 0.2 kg. What is the final temperature of the water when the system come to equilibrium. See the equation [3] in the manual. Here use cc=900 J/kg°C, Cw=4186 J/kg°C and Ci=2090 J/kg°C. And L=333000 J/kg The answer keep one digit under decimal point. (For example 10.3)
Calculate the final equilibrium temperature when 10.0 grams of steam initially at 100 degree C is mixed with 450 grams of liquid water and 110 grams of ice at 0 degree C in a calorimeter. That is, the liquid water AND the ice are initially at 0 degree C. Ignore any heat energy exchanges with the calorimeter and the surroundings. If you conclude that the final temperature of the system is 0 degree C, then what mass of ice remains,...
To cool her 0.200 kg cup of 75.0 C hot chocolate (mostly water), Heidi drops a 29,.97 g ice cube at 0 C into her insulated cup. After the ice cube melts, the temperature of the hot chocolate comes down to 54.8 C. a. How much energy was lost by the hot chocolate? The specific heat capacity of water is 1 cal/g C b. How much energy was gained by the ice cube just to melt to 0 C water?...
1) An aluminum calorimeter of
mass 58 g, has 155 g water, both at a temperature of 21°C. A 108-g
piece of metal originally kept in boiling water (T = 100°C) is
transferred to the calorimeter. The final equilibrium temperature
of the mixture is 26.6°C. Calculate the specific heat of the metal
(in J/kg). Specific Heats: Al = 900 J/kg, water =4186 J/g
2) How much heat, in kilo-joules, is required to convert 19 g of
ice at -13°C into...
How much ice is in the final state after 2 kg of ice at -30°C is added to a large quantity of water at 0°C? The final state is ice-water. (The temperature of the ice increases to 0°C and some of the water freezes.) J For water : Cice = 4186 J kg.K If = 3 = 2100 kg.K : Cwater L, = 2.26 x 106 .34 x 10% J kg 9 kg
Check What mass of water at 250°C added to a Styrofoam cup containing two 53.3-gice cubes from a freezer at 16.6°C will result in a final temperature of 5.00°C for the drink? The specific heat of ice is 2.10 Jak and that of water is 4.186 JK The latent heat of ice is 3337 J/g. points 19