Question

Report average and %RSD for the standardization of your NaOH concentration if 9.9694g of solid NaOH is weighed out diluted with water then mixed until the solid is completely dissolved. The analyte is made by adding about 75 mL of water and 25 ml of HCl.

Trial 1: 14.7 mL titrant

Trial 2: 11.6 mL titrant

Trial 3: 12.1 mL titrant

The goal is to standardize a 0.5 M NaOH solution against a 0.25 mL standard HCl solution.

Answer 1

% RSD =

Let X1= 14.7 ml

X2= 11.6 ml

X3 = 12.1 ml

Mean (Xi)=

Where N is number of titrant values,

Xi =

=12.8

Standard deviation (S D) =sqare root of

=square root of

S D = square root of

S D = square root of (2.77)

S D = 1.66

RSD =

RSD = 0.1300

% RSD = 0.13 × 100

% RSD = 13%

In formula XiXi means (X_i)²

and X1 means X1 means X_{i i couldn't type so i have substituted at last}