Question

Be sure to answer all parts. How would you prepare 2.10 × 102 mL of a 0.726 M NaOH solution, starting with a 5.98 M stock solution? Volume of stock solution needed: mL Volume of water needed: mL

Answer 1

1)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 5.98 M

M2 = 0.726 M

V2 = 210 mL

use:

M1*V1 = M2*V2

V1 = (M2 * V2) / M1

V1 = (0.726*210)/5.98

V1 = 25.5 mL

Answer: 25.5 mL

2)

volume of water = V2 - V1

= 210 mL - 25.5 mL

= 184.5 mL

Answer: 184 mL