Question

Identify the acid, base and its conjugated pairs for the following reactions:

1. HClO₂(ac) + NaIO(ac)    →    HIO(ac) +  NaClO₂(ac)
2. HS^-(ac) + HF(ac)    →    H₂S(ac) + F^-(ac)
3. HS^-(ac) + OH^-(ac)    →    S₂^-(ac) + H₂O(l )

Answer 1

keep in mind acid is proton donar and base is proton acceptor

1) for reaction HClO₂ + NaIO   HIO + NaClO₂ in this reaction HClO donate proton to NaIO therefore in this reaction HClO₂ is acid and after donation of proton it 's conjugate base is ClO₂^- which forms ionic bond with Na⁺ to form NaClO₂  

ans here HClO₂ is acid and ClO₂^- is conjugate base of HClO₂  

here NaIO is base and HIO is conjugate acid

2) for reaction HS + HF   H₂S + F^-  

in this reaction HF donate proton to HS hence HF acts as acid and after donation of proton F^- is conjugate base formed from HF

in this reaction HS accept proton from HF hence HS acts as a base and after accepting proton HS converts into H₂S therefore H₂S is conjugate acid of base HS

ans here HF is acid and F^- is conjugate base

HS is base and H₂S is conjugate acid

3) for reaction HS_(ac) + OH^-_(ac)   S^2-_(ac) + H₂O_(l)     

in this reaction HS donate proton to OH^- hence HS acts as acid and after donation of proton S^- is conjugate base formed from HS

in this reaction OH^- accept proton from HS hence OH^- acts as a base and after accepting proton OH^- converts into H₂O therefore H₂O is conjugate acid of base OH^-  

ans here HS is acid and S^- is conjugate base

OH^- is base and H₂O conjugate acid