Question

1. a) How many mL of 6.00 ppm solution are needed to make 4.00 L of a 0.100 ppm solution?

b) What is the dilution factor?

Answer 1

1.

a)

From a solution of 6.00 ppm we have to prepare a solution of 4.00L of 0.100 ppm.

Initial concentration of the solution (N₁) is 6.0 ppm

Final concentration of the solution (N₂) is 0.1 ppm

Final volume of the solution (V₂) is 4L = 4000 mL

We don't know the initial volume (V_{​​​​​1}) that we need to take to make the final solution,

We need to calculate the initial volume by following equation,

N₁V₁ = N₂​​​​​​V₂

V₁ = (N₂V₂) / N₁

V₁ = (0.1 ppm × 4000 mL) / 6.0 ppm

V₁ = 66.66 mL

So we need 66.66 mL of 6.0 ppm solution to make 4.0 L of 0.1 ppm solution.

b)

We can calculate the dilution factor by the following formula,

Dilution factor = final volume / initial volume

Dilution factor = 4000 mL / 66.66 mL = 60.006

The dilution factor is 60.006.