A study reports that 36% of companies in Country A have three or more female board directors. Suppose you select a random sample of 100 respondents. Complete parts (a) through (c) below.
The probability is 99.7% that the sample percentage of Country A companies having three or more female board directors will be contained within what symmetrical limits of the population percentage?
The probability is 99.7% that the sample percentage will be contained above ____and below ____(Round to one decimal place as needed.)
Sample proportion (\hat{p}) = 0.36
Sample size (n) = 100
Confidence interval(in %) = 99.7%
z @ 99.7% = 3.0
Since we know that

Required confidence interval = (0.36-0.144, 0.36+0.144)
Required confidence interval = (21.6, 50.4)
Please hit thumps up if the answer helped you.
A study reports that 36% of companies in Country A have three or more female board...