Question

A 0.300 kg ice puck, moving east with a speed of 2.90 m/s , has a head-on collision with a 0.900 kgpuck initially at rest.

a) Assuming a perfectly elastic collision, what will be the speed of the 0.300 kg object after the collision?

b)What will be the direction of the 0.300 kg object after the collision?

c,What will be the speed of the 0.900 kg object after the collision?

d) What will be the direction of the 0.900 kg object after the collision?

Answer 1

A)

V1 = ((0.3 - 0.9)/(0.3 + 0.9)) x 2.9 = 1.45 m/s

B)

Towards west

C)

V2 = ((2 x 0.3)/(0.3 + 0.9)) x 2.9 = 1.45 m/s

D)

Towards east

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