Question

Two circuits are placed near to one-another. When a current I1(t) that increases linearly from 1.1 to 2.2 A over a time of 20 ms flows in the first circuit, there is an observed electromotive force in the second circuit of 16 V. What is the mutual inductance of the two circuits?

Answer 1

Induced emf in second circuit is given by:

E₂₁ = M₂₁*di₁/dt

16 = M*[2.2-1.1]/20e-3

M = 16*20e-3/[2.2-1.1]

= 0.291 H answer