When one mole of an ideal gas is compressed reversibly and adiabatically to half of its original volume, the temperature of the gas increases from 273 K to 433 K. Calculate CV for this gas, assuming that it is temperature independent.
Is this gas monatomic or diatomic?
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As we know for adiabatic reversible compression of a gas,
.....................(1)
Also,
.......................(2)
Cp = Cv + R...................(3)
So substituting,
Tf = 433 K
Ti = 273 K
2Vf = Vi
in (1), we get
= 1.23
Using the above obtained value of γ and equations (2) and (3) we get,
R= 8.314 J K-1 mol-1
Cv = 36.15 J K-1 kg-1
As we can see
= 1.23 .
Thus we can say that the gas is diatomic.
When one mole of an ideal gas is compressed reversibly and adiabatically to half of its...