Question

A ball is launched straight upward with an initial speed of 28 m/s. How high is it 1.9 seconds later?

The answer is 36 m. Can you show me step by step solution to solve this problem?

Answer 1

Given,

The initial speed of the ball, u = 28 m/s

Time = 1.9 s

Acceleration due to gravity,

Since the ball is going upward hence there will be de-acceleration in the ball so from the equation of the motion the height reached by the ball can be given by

  

  

  

Hence the height reached by the ball in 1.9 seconds is 36 m approx.