Question

Calculate the acid dissociation constant K(hx) of HX at 25C. Given the following:

* equivalent conductivty at infinite dilution of an unknown salt of potassium with formula unit KX is calculated to be 95.0 x10^-4 Sm^2eq^-1 at 25C.

* a conductivity cell with a cell constant (L/A) = 50 m^-1 that is filled with 0.001M of the acid of X, HX

*HX is the weak acid

* resistance at 25 degrees C was measured to be 1950 Ohm

* equivalent conductivities at infinite dilution for HCL and KCL are 426.4 x 10^-4Sm^2eq^-1 and 149.9 x 10^-4 Sm^2eq^-1

Answer 1