Question

Please help with this problem, been stuck for a couple of days. What should the 6 digits be in order to difuse this Phase_2?

Dump of assembler code for function phase_2:
0x0000000000400afd <+0>: push %rbp               
0x0000000000400afe <+1>: mov %rsp,%rbp           
0x0000000000400b01 <+4>: sub $0x30,%rsp          
0x0000000000400b05 <+8>: mov %rdi,-0x28(%rbp)
0x0000000000400b09 <+12>: lea -0x20(%rbp),%rdx
0x0000000000400b0d <+16>: mov -0x28(%rbp),%rax
0x0000000000400b11 <+20>: mov %rdx,%rsi
0x0000000000400b14 <+23>: mov %rax,%rdi
0x0000000000400b17 <+26>: callq 0x40104e <read_six_numbers>
0x0000000000400b1c <+31>: mov -0x20(%rbp),%eax
0x0000000000400b1f <+34>: test %eax,%eax
0x0000000000400b21 <+36>: jns 0x400b28 <phase_2+43>
0x0000000000400b23 <+38>: callq 0x4013ac <explode_bomb>
0x0000000000400b28 <+43>: movl $0x1,-0x4(%rbp)
0x0000000000400b2f <+50>: jmp 0x400b58 <phase_2+91>
0x0000000000400b31 <+52>: mov -0x4(%rbp),%eax
0x0000000000400b34 <+55>: cltq
0x0000000000400b36 <+57>: mov -0x20(%rbp,%rax,4),%edx
0x0000000000400b3a <+61>: mov -0x4(%rbp),%eax
0x0000000000400b3d <+64>: sub $0x1,%eax
0x0000000000400b40 <+67>: cltq
0x0000000000400b42 <+69>: mov -0x20(%rbp,%rax,4),%ecx

this assembly language is in C. i do not need to code it but deduce which values it reads (1-6). figure out the pattern.

Answer 1

This one was rather tricky after an easy step one. First, we found that it was looking for 6 numbers, from the scanf function looking 6 times. We eventually figured out that it the code consisted of a repeat of 3 decreasing numbers. 10 9 8 10 9 8, for example. That did the trick for us.

Solution: 10 9 8 10 9 8