ABC 1 2 3 4 5 6 7 8 9 10 11 12 13 Chapter 13: Applying Excel Data Example E Cost of equipment needed $230,000 Working capital needed $30,000 Overhaul of equipment in four years $20,000 Salvage value of the equipment in five years $25,000 Annual revenues and costs: Sales revenues $420,000 Cost of goods sold $270,000 Out-of-pocket operating costs $80,000 Discount rate 15 % What is the net present value of the project? The internal rate of return is between what two whole discount rates (e.g., between 10% and 11%, between 11% and 12%, between 12% and 13%, between 13% and 14%, etc.)? Reset the discount rate to 15%. Suppose the salvage value is uncertain. How large would the salvage value have to be to result in a positive net present value?

| year | 0 | 1 | 2 | 3 | 4 | 5 |
| cost of equipment | -230000 | |||||
| working capital investment | -30000 | |||||
| annual revenue | 420000 | 420000 | 420000 | 420000 | 420000 | |
| cost of goods sold | 270000 | 270000 | 270000 | 270000 | 270000 | |
| operating cost | 80000 | 80000 | 80000 | 80000 | 80000 | |
| operating profit | 70000 | 70000 | 70000 | 70000 | 70000 | |
| overhaul expense | -20000 | |||||
| salvage value | 25000 | |||||
| recovery of working capital | 30000 | |||||
| net operating cash flow | -260000 | 70000 | 70000 | 70000 | 50000 | 125000 |
| present value factor at 15% =1/(1+r)^n | 1 | 0.869565217 | 0.756143667 | 0.6575162 | 0.571753246 | 0.497177 |
| present value of cash flow = net operating cash flow*present value factor | -260000 | 60869.56522 | 52930.05671 | 46026.136 | 28587.66228 | 62147.09 |
| NPV =sum of present value of cash flow | -9439.48761 | |||||
| IRR =Using IRR function in MS excel | IRR(C829:H829) | 13.56% | ||||
| IRR should be in the range of between 13% & 14% | ||||||
| Future value of amount of shortage of NPV to be positive | Shortage of amount for positive NPV*(1+r)^n r =15% | 9439.4876*1.15^5 | 18986.18123 | |||
| value of salvage value for positive NPV | 18986.18+25000 | 43986.18 |