Why are two equivalents of benzaldehyde and one equivalent of acetone used in a aldol condensation? Why not 1 to 1? What would the products be if 1:1 used?
Benzaldehyde reacts with Acetone in presence of base to form Aldol.
First part:
In presence of base, an an ion is generated on the -CH3 group of acetone and this an ion adds across carbonyl group of Benzaldehyde by a nucleophilic addition which results in the formation of Aldol and it subsequently eliminates one molecule of water to form an unsaturated ketone.
Second part:
The other -CH3 group in the above unsaturated ketone again ionizes to form a -CH2 anion which reacts with a second molecule of Benzaldehyde by a nucleophilic addition way to form Aldol and it again eliminates a molecule of water to form final product.
Therefore, two molecules of Benzaldehyde with one molecule of Acetone are required for completion of reaction.
A mechanistic scheme is attached herewith

Why are two equivalents of benzaldehyde and one equivalent of acetone used in a aldol condensation?...