In physics lab, a force of 175.7 N is applied to a 7.2 kg cart to accelerate it across a horizontal surface at a rate of 5 m/s^2.
What is the net force acting on the cart? F net =___________ unit__________
What is the force of friction acting on the cart? F friction =____________ unit__________
According to the equation of motion

where, m is the mass of the cart, a is the acceleration of the cart
and
is the net
force acting on the cart.
And net force is given by
where,
is the
applied force and
is the
frictional force and the relative negative sign between the two is
because frictional force acts in the opposite direction to the
applied force. And so,
putting the given values,
i)
we get the net force as

ii)
Frictional force is given by
so, putting the values, we get

In physics lab, a force of 175.7 N is applied to a 7.2 kg cart to...