Question

The rules of the game is flip one quarter coin a total of ten times each person.  It's a game playing with total of two people (A and B).

The winner is the one who got most head side on the coin.

Question 1) If player A and B, play the fair game what is the expected value?

Question 2) A and B threw the coin 10 times each. The results are below. It's a game the person who got more head side is become a winner.  What is the expected value of this game? A: head -> 7 out of 10times

Tails -> 3 out of 10times

  B: head-> 2 out of 10 times

Tails -> 8 out of 10 times

Answer 1

1.

p(heads in one toss) = 0.5

no. of tosses (n) = 10

expected value = p*n

= 0.5*10

= 5 heads

2.

expected value of this game = n*p = 10*0.5 = 5 heads

A:

head -> 7 out of 10times

Tails -> 3 out of 10times

B:

head-> 2 out of 10 times

Tails -> 8 out of 10 times

according to this A will win as no. of heads of A is more

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