Question

Code a class called tree, code an overloaded constructor that accepts tree name, width and height. the overloaded will print "rainbow" "6ft""200 ft" JAVA

Answer 1

Java code for creating the class and the overloaded constructor as mentioned in the question with the comments above is below :-

public class tree //tree class with the variable members defined
{
String tree_name;
String tree_width;
String tree_height;

tree() //Default constructor without parameters
{

tree_name = "Papaya";
tree_width = "8ft";
tree_height = "200 ft";
}

tree(String name, String width, String height) //constructor with the parameters
{

tree_name = name;
tree_width = width;
tree_height = height;
}

public String gettreeName()
{
return tree_name;
}

public String gettreeWidth()
{
return tree_width;
}

public String gettreeheight()
{
return tree_height;
}



public static void main(String args[])
{
//object creation and calling the constructor without parameter
tree obj1 = new tree();   

//object creation and calling the constructor with parameters
tree obj2 = new tree("rainbow", "6ft", "200 ft");
System.out.println("tree name is: " + obj2.gettreeName());
System.out.println("tree width is: " + obj2.gettreeWidth());
System.out.println("tree height is: " + obj2.gettreeheight());
}
}

Explanation :-

Overloaded constructor : Overloaded constructors are when more than one constructor are being defined with different signatures i.e. no or different parameters defined . Overloaded constructors have the same name but have different parameter signatures defined . For example , one constructor can have no parameters , second can have one parameter passed , third can have two or more parameters defined and so on .

In the above example following are the execution points :-

1) When the control goes to the main method in the class tree , there first an object obj1 is created which calls the constructor with the name tree which has no arguments passed to it . In that constructor the values to the name , width , height are set as "Papaya" ,  "8ft" , "200 ft". But they are not printed as using the object obj1 the get methods are not called in the pritnln statement .

2) Next the second object obj2 is created which calls the constructor in which the parameters are defined . Therefore , when the constructor is called the values are passed and are assigned to the member variables of the class tree i.e. tree_name , tree_width , tree_height . Then the three println statements are executed in which the values of the passed parameters ie. name , width , height are printed by calling the get method using the second object i.e. obj2 . Therefore in the display screen the values rainbow , 6ft , 200 ft are printed .

Screenshot of the above code execution :-