A box have 20 tickets, including 4 winning tickets. Two people take 2 tickets from the box randomly. calculate the probability that each person will get at least 1 winning ticket (using counting, permutations and combinations)
Below 3 Scenarios are possible:
2W and 2 L
3 W and 1 L
4 W
P(1) = (4C2 * 16C2 * ½)/20C4 = 0.074
P(2) = 4C3 /20C4 = 0.001
P(3) = 4C4 /20C4 = 0.0002
Hence, P = P(1) + P(2) + P(3) = 0.075 or 7.5%
A box have 20 tickets, including 4 winning tickets. Two people take 2 tickets from the...