Question

A student ran the following reaction in the laboratory at 277 K:

2CH₂Cl₂(g) = CH₄(g) + CCl₄(g)

When she introduced 6.91×10^-2 moles of CH₂Cl₂(g) into a 1.00 liter container, she found the equilibrium concentration of CCl₄(g) to be 3.24×10^-2 M.

Calculate the equilibrium constant, K_c, she obtained for this reaction.

K_c =

Answer 1