A 1220-kg car pulls a 390-kg trailer. The car exerts a horizontal force of 3.6 × 103 N against the ground in order to accelerate.
What force does the car exert on the trailer? Assume an effective friction coefficient of 0.19 for the trailer.
writing the force equation we have
F - u*1200*g - T = 1200a -------(1)
T - u*390*g = 390a ---------(2)
adding both we have
3600 - 0.19*1590*9.8 = 1590a
a = 0.507 m/s2
T = 0.19*390*9.8 + 390*0.507
T = 923.9 N
so the force that the car exerts on the trailer is 923.9 N
A 1220-kg car pulls a 390-kg trailer. The car exerts a horizontal force of 3.6 ×...