Launch a tennis ball at 120 mph, from the ground level. You get horizontal range of 115 m. Find
the initial launch angle.
Launch a tennis ball at 100 mph, from the ground level. You get a maximum height of
50 m. Find
the initial launch angle.
explain steps!!!
A)
120 mph = 53.64 m/s
Range, R = u^2 sin(2 theta)/g
115 = 53.64^2 sin(2 theta)/9.8
Theta = 11.53°
B)
100 mph = 44.7 m/s
H = (u sin(theta))^2/2g
50 = (44.7 sin(theta))^2/(2 x 9.8)
(44.7 sin(theta))^2 = 50 x 2 x 9.8 = 980
Taking square root both sides,
44.7 sin(theta) = 31.30
Sin(theta) = 0.7
Theta = arcsin(0.7)
Theta = 44.45°
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Launch a tennis ball at 120 mph, from the ground level. You get horizontal range of...