Find the order of the reaction for the dye and the units for k'.
I am not sure what data is needed so I just paste them all, hope it helps, thank you!
Rate = k[dye]m[OCl-]n
Rate = k'[dye]m where k' =
k[OCl-]n
Molar concentration of the dye stock solution: 2.52e-5 mol/L
Operating Wavelength: 631 nm
| Solutions | Volume(mL) of Blue#1 stock solution | Volume(mL) of distilled H20 | Absorbance (A) (a.u.) |
| 1 |
1.00 |
19.00 | 0.052 |
| 2 | 2.00 | 18.00 | 0.121 |
| 3 | 4.00 | 16.00 | 0.213 |
| 4 | 8.00 | 12.00 | 0.537 |
[dye] = 1.96×10-5x A
| Solutions (Dilutions) |
OCl- Concentration mol/L |
|---|---|
| Experiment 1 | 0.034 |
| Experiment 2 | 0.067 |
| Experiment 3 |
0.13 |
| Experiment 1 | ||
|---|---|---|
| Time (s) |
Absorbance (a.u.) |
[dye] (mol/L) x 10-6 |
| 15 | 0.980 | 19.2 |
| 30 | 0.941 | 18.4 |
| 45 | 0.909 | 17.8 |
| 75 | 0.849 | 16.6 |
| 90 | 0.808 | 15.8 |
| 105 | 0.781 | 15.3 |
| 120 | 0.750 | 14.7 |
| 135 | 0.721 | 14.1 |
| 150 | 0.690 | 13.5 |
| 165 | 0.660 | 12.9 |
| Experiment 2 | ||
|---|---|---|
| Time (s) |
Absorbance (a.u.) |
[dye] (mol/L) x 10-6 |
| 15 | 0.863 | 16.9 |
| 30 | 0.789 | 15.4 |
| 45 | 0.720 | 14.1 |
| 60 | 0.652 | 12.8 |
| 75 | 0.592 | 11.6 |
| 90 | 0.538 | 10.5 |
| 105 | 0.486 | 9.51 |
| 120 | 0.441 | 8.63 |
| 135 | 0.397 | 7.77 |
| 150 | 0.358 | 7.01 |
| Experiment 3 | ||
|---|---|---|
| Time (s) |
Absorbance (a.u.) |
[dye] (mol/L) x 10-6 |
| 10 | 0.747 | 14.6 |
| 20 | 0.649 | 12.7 |
| 30 | 0.563 | 11.0 |
| 40 | 0.486 | 9.51 |
| 50 | 0.418 | 8.18 |
| 60 | 0.361 | 7.06 |
| 70 | 0.310 | 6.07 |
| 80 | 0.267 | 5.22 |
| 90 | 0.228 | 4.46 |
| 100 | 0.197 | 3.85 |
The order of above reaction is 2 i.e. reaction a second order
and the unites of K for second order reaction are
where M is mole and s in seconds.
Find the order of the reaction for the dye and the units for k'. I am...