Question

A car starts from rest in the pit area and accelerates at a uniform rate to a speed of 35 m/s in 11 s, moving on a circular track of radius 500 m. Determine the tangential and centripetal components of the net force exerted on a car by the ground when is speed is 15 m/s. The car’s mass is 950 kg. (Assume constant tangential acceleration).

Answer 1

a)

From Kinematic equation

V=V_o+at

Since it starts from rest V_o=0

Therefore Tangential acceleration

35=0+a_t*11

a_t=35/11 =3.182 m/s²

Tangential force

F_t = ma = 950*3.182 =3022.73 N

b)

Centripetal acceleration is

a_c=V²/r =15²/500 =0.45 m/s²

Centripetal fore is given by

F_c=ma =950*0.45 =427.5 N