You cause a particle to move from point A, where the electric potential is 12.7 V, to point B, where the electric potential is − 29.7 V. Calculate the change that occurs in the particle's electrostatic potential energy, when the particle is an electron, a proton, a neutral hydrogen atom, and a singly ionized helium atom (i.e., lacking one electron from its neutral state).
Electron =
Proton =
Neutral Hydrogen Atom =
Electron =
Singly ionized helium atom (i.e., lacking one electron from its neutral state) =
va=12.7v
vb=-29.7v
change in potential=vb-va
= -29.7-12.7
=-42.4v
a)q=-1.6*10^-19c
electrostatic potential energy=potential difference*charge
=-1.6*10^-19*(-42.4)J
=67.8*10^-19J
b) for proton change in electrostatic potential energy is
-67.8*10^-19J
c)for neutral hydrogen atom change in electrostatic potential energy is zero (q=0c)
d)singly ionized helium atom q=1.6*10^-19c
change in electrostatic potential energy is =-67.8*10^-19J
You cause a particle to move from point A, where the electric potential is 12.7 V,...