A researcher transfers a 15-mL aliquot of a base (Solution X) with unknown concentration into a beaker and adds approximately 20 mL of distilled water. The researcher then titrates the solution with 0.100 M standard HCl solution and tracks the pH of the solution during the titration with a pH meter. Equivalence point volume occurs when 25ml of HCl is added. From MaVa=MbVb, we know that the molarity of Solution X is 0.0714M.
| Volume of HCl added (mL) | pH of solution |
| 0 | 11.3 |
| 5 | 9.86 |
| 10 | 9.44 |
| 15 | 9.08 |
| 20 | 8.66 |
| 22 | 8.39 |
| 24 | 7.88 |
| 24.5 | 6.7 |
| 25 | 5.28 |
| 25.5 | 4 |
| 26 | 2.7 |
| 28 | 2.22 |
| 30 | 2.01 |
| 35 | 1.7 |
| 40 | 1.52 |
| 45 | 1.4 |
| 50 | 1.3 |
1) Which base from the list of the bases provided below was the researcher most likely given?
Provide a one or two sentence explanation of your answer.
Base Kb
NaOH Kb >>1
Ethylamine 7.4×10−4
Ammonia 1.8×10−5
Pyridine 5.6×10−8
Sodium Acetate 5.6×10−10
Sodium fluoride 1.6×10−11
Potassium sulfate 8.3×10−13
2) What would happen to the equivalence point pH if using a 0.200 M HCl solution rather than a 0.100 M HCl solution to titrate the solution?
A researcher transfers a 15-mL aliquot of a base (Solution X) with unknown concentration into a...