LINEAR PROGRAMMING
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A farmer in Wood County has 950 acres of land. She is going to plant each acre with corn, soybeans, or wheat. Each acre planted with corn yields a $2,200 profit; each with soybeans yields $2,450 profit; and each with wheat yields $3,150 profit. She has 192 workers and 195 tons of fertilizer. The table below shows the requirement per acre of each of the crops. |
| CORN | SOYBEANS | WHEAT | |
| Labor (workers) | 0.2 | 0.2 | 0.4 |
| Fertilizer (tons) | 0.2 | 0.3 | 0.2 |
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Assuming a linear relationship, use Excel Solver to determine the optimal planting mix of corn, soybeans, and wheat to maximize her profits. In formulating your linear program, do NOT restrict the three decision variables to integer values. (However, round the final values of these decision variables to the nearest whole number when entering those answers. Use these rounded decision variable values to compute “Total Profit” and enter that answer to the nearest whole number. Lastly, also use the rounded decision variable values to compute the three “Resources Used” answers and enter them to the nearest whole number. Leave no cells blank – be certain to enter “0” wherever required.) |
| Decision for corn | |
| Decision for soybeans | |
| Decision for wheat | |
| Total profit | $ |
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Resources Used |
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| Labor (workers) | |
| Fertilizer (tons) | |
| Acres Planted | |
Spreadsheet model and solution using Solver is following:

FORMULAS:
E3 =SUMPRODUCT(B3:D3,$B$10:$D$10) copy to E5:E7
Optimal result:
Decision for Corn = 890
Decision for Soybeans = 50
Decision for Wheat = 10
Total profit = $ 2,112,000
Resources used
Labor (workers) = 890*.2+50*.2+10*.4 = 192
Fertilizer (tons) = 890*.2+50*.3+10*.2 = 195
Acres planted = 890+50+10 = 950
LINEAR PROGRAMMING A farmer in Wood County has 950 acres of land. She is going to...