Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...

Question

Question

Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...

Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389 kJ/mol; O-H, 464 kJ/mol, calculate ∆Hrxn. 2NO(g) + 5H2(g)  2NH3(g) + 2H2O(g) Answer: -759 kJ

Please work out how you did it

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

Add a comment

Answer 2

Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...

Homework Answers

Add Answer to:
Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...

Post as a guest

Earn Coins

Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...

Homework Answers

Add Answer to: Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...

Post as a guest

Earn Coins

Add Answer to:
Given the bond energies, N to O in NO, 628 kJ/mol; H-H, 435 kJ/mol; N-H, 389...