Question

Find the flux of Earth's magnetic field of magnitude 5.00 ✕ 10⁻⁵ T through a square loop of area 30.0 cm² for the following:

(a) when the field is perpendicular to the plane of the loop
  T · m²

(b) when the field makes a 36.5° angle with the normal to the plane of the loop
T · m²

Answer 1

Solution)

Given,

Magnetic Field, B=5*10^-5 T

Area=30*10^-4 m^2

Part a)

Here, Theta=0°

We know, Flux=BA costheta

Substituting values

Flux=(5*10^-5 T)*(30*10^4 m^2)*cos0= 1.5*10^-7 T-m^2 (Ans)

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Part b)

Here, theta=36.5°

So, Flux=(5*10^-5)*(30*10^-4)*cos36.5= 1.2*10^-7 Tm^2 (Ans)

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