Question

A parallel-plate capacitor is made from two aluminum-foil sheets, each 5.8 cm wide and 5.7 m long. Between the sheets is a Teflon strip of the same width and length that is 4.0×10⁻² mm thick. What is the capacitance of this capacitor? (The dielectric constant of Teflon is 2.1.)

I used formula C = (k)(E_o)(A) / (d) with C = (2.1)(8.85 x 10^-12)(0.058)(12) / (4.0 x 10^-5) and got C = 3.23 x 10^-7 F. The answer needs to be in micro F so I converted that to micro F and got 0.323 micro F but the answer is wrong... can someone please tell me what I am doing wrong? Show all work/explain for points.

Answer 1