Question

How many grams of MgI 2 are produced by the reaction of 25.0 g of Mg with 25.0 g of I 2? Mg + I 2 mc002-1.jpg MgI 2

a. 195 g

b. 9.20 g

c. 18.4 g

d. 27.4 g

e. 49.0 g

Answer 1

let x be the mass oof I2 required by 25 g of Mg

24 g of Mg requires-----> 253.8089 g of I2

25 g of Mg requires-----> x g of I2

cross multiply

24*x=253.8089*25

x=264.38427 g of I2

But we have only 25 g of I2. so I2 is the limiting reagent

let y be the amount of MgI2 produced by 25 g of I2

253.8089 g of I2 gives----> 277.8089 g of MgI2

25 g of I2 gives----> y g of MgI2

cross multipy

253.8089*y=277.8089*25

y= 27.4 g of MgI2 is produced.