A methods and measurements analyst needs to develop a time standard for a certain task. In a preliminary study, he observed one of his workers perform this task five times, with the following results:
| Observation | 1 | 2 | 3 | 4 | 5 |
| Time (secs) | 81 | 79 | 75 | 83 | 84 |
What is the standard time for this task if the employee worked at a 29 percent faster pace than average and an allowance of 16 percent of the workday is used?
(Keep one decimal place in your answer)
Average of given time,
Observed time = 81+79+75+83+84 / 5 = 80.4
Normal time = Observed time * Performance rating = 80.4 * 1.29 = 103.716
Allowance factor = 1 / 1 - 0.16 = 1.19
Standard time = 103.716 * 1.19 = 123.4 seconds.
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A methods and measurements analyst needs to develop a time standard for a certain task. In...